3.6.4 \(\int \frac {1}{(d+e x)^3 (a+c x^2)} \, dx\) [504]

Optimal. Leaf size=176 \[ -\frac {e}{2 \left (c d^2+a e^2\right ) (d+e x)^2}-\frac {2 c d e}{\left (c d^2+a e^2\right )^2 (d+e x)}+\frac {c^{3/2} d \left (c d^2-3 a e^2\right ) \tan ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {a}}\right )}{\sqrt {a} \left (c d^2+a e^2\right )^3}+\frac {c e \left (3 c d^2-a e^2\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^3}-\frac {c e \left (3 c d^2-a e^2\right ) \log \left (a+c x^2\right )}{2 \left (c d^2+a e^2\right )^3} \]

[Out]

-1/2*e/(a*e^2+c*d^2)/(e*x+d)^2-2*c*d*e/(a*e^2+c*d^2)^2/(e*x+d)+c*e*(-a*e^2+3*c*d^2)*ln(e*x+d)/(a*e^2+c*d^2)^3-
1/2*c*e*(-a*e^2+3*c*d^2)*ln(c*x^2+a)/(a*e^2+c*d^2)^3+c^(3/2)*d*(-3*a*e^2+c*d^2)*arctan(x*c^(1/2)/a^(1/2))/(a*e
^2+c*d^2)^3/a^(1/2)

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Rubi [A]
time = 0.11, antiderivative size = 176, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.294, Rules used = {724, 815, 649, 211, 266} \begin {gather*} \frac {c^{3/2} d \text {ArcTan}\left (\frac {\sqrt {c} x}{\sqrt {a}}\right ) \left (c d^2-3 a e^2\right )}{\sqrt {a} \left (a e^2+c d^2\right )^3}-\frac {c e \left (3 c d^2-a e^2\right ) \log \left (a+c x^2\right )}{2 \left (a e^2+c d^2\right )^3}-\frac {2 c d e}{(d+e x) \left (a e^2+c d^2\right )^2}-\frac {e}{2 (d+e x)^2 \left (a e^2+c d^2\right )}+\frac {c e \left (3 c d^2-a e^2\right ) \log (d+e x)}{\left (a e^2+c d^2\right )^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/((d + e*x)^3*(a + c*x^2)),x]

[Out]

-1/2*e/((c*d^2 + a*e^2)*(d + e*x)^2) - (2*c*d*e)/((c*d^2 + a*e^2)^2*(d + e*x)) + (c^(3/2)*d*(c*d^2 - 3*a*e^2)*
ArcTan[(Sqrt[c]*x)/Sqrt[a]])/(Sqrt[a]*(c*d^2 + a*e^2)^3) + (c*e*(3*c*d^2 - a*e^2)*Log[d + e*x])/(c*d^2 + a*e^2
)^3 - (c*e*(3*c*d^2 - a*e^2)*Log[a + c*x^2])/(2*(c*d^2 + a*e^2)^3)

Rule 211

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/Rt[a/b, 2]], x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 266

Int[(x_)^(m_.)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> Simp[Log[RemoveContent[a + b*x^n, x]]/(b*n), x] /; FreeQ
[{a, b, m, n}, x] && EqQ[m, n - 1]

Rule 649

Int[((d_) + (e_.)*(x_))/((a_) + (c_.)*(x_)^2), x_Symbol] :> Dist[d, Int[1/(a + c*x^2), x], x] + Dist[e, Int[x/
(a + c*x^2), x], x] /; FreeQ[{a, c, d, e}, x] &&  !NiceSqrtQ[(-a)*c]

Rule 724

Int[((d_) + (e_.)*(x_))^(m_)/((a_) + (c_.)*(x_)^2), x_Symbol] :> Simp[e*((d + e*x)^(m + 1)/((m + 1)*(c*d^2 + a
*e^2))), x] + Dist[c/(c*d^2 + a*e^2), Int[(d + e*x)^(m + 1)*((d - e*x)/(a + c*x^2)), x], x] /; FreeQ[{a, c, d,
e, m}, x] && NeQ[c*d^2 + a*e^2, 0] && LtQ[m, -1]

Rule 815

Int[(((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_)))/((a_) + (c_.)*(x_)^2), x_Symbol] :> Int[ExpandIntegrand[(
d + e*x)^m*((f + g*x)/(a + c*x^2)), x], x] /; FreeQ[{a, c, d, e, f, g}, x] && NeQ[c*d^2 + a*e^2, 0] && Integer
Q[m]

Rubi steps

\begin {align*} \int \frac {1}{(d+e x)^3 \left (a+c x^2\right )} \, dx &=-\frac {e}{2 \left (c d^2+a e^2\right ) (d+e x)^2}+\frac {c \int \frac {d-e x}{(d+e x)^2 \left (a+c x^2\right )} \, dx}{c d^2+a e^2}\\ &=-\frac {e}{2 \left (c d^2+a e^2\right ) (d+e x)^2}+\frac {c \int \left (\frac {2 d e^2}{\left (c d^2+a e^2\right ) (d+e x)^2}+\frac {3 c d^2 e^2-a e^4}{\left (c d^2+a e^2\right )^2 (d+e x)}+\frac {c \left (d \left (c d^2-3 a e^2\right )-e \left (3 c d^2-a e^2\right ) x\right )}{\left (c d^2+a e^2\right )^2 \left (a+c x^2\right )}\right ) \, dx}{c d^2+a e^2}\\ &=-\frac {e}{2 \left (c d^2+a e^2\right ) (d+e x)^2}-\frac {2 c d e}{\left (c d^2+a e^2\right )^2 (d+e x)}+\frac {c e \left (3 c d^2-a e^2\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^3}+\frac {c^2 \int \frac {d \left (c d^2-3 a e^2\right )-e \left (3 c d^2-a e^2\right ) x}{a+c x^2} \, dx}{\left (c d^2+a e^2\right )^3}\\ &=-\frac {e}{2 \left (c d^2+a e^2\right ) (d+e x)^2}-\frac {2 c d e}{\left (c d^2+a e^2\right )^2 (d+e x)}+\frac {c e \left (3 c d^2-a e^2\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^3}+\frac {\left (c^2 d \left (c d^2-3 a e^2\right )\right ) \int \frac {1}{a+c x^2} \, dx}{\left (c d^2+a e^2\right )^3}-\frac {\left (c^2 e \left (3 c d^2-a e^2\right )\right ) \int \frac {x}{a+c x^2} \, dx}{\left (c d^2+a e^2\right )^3}\\ &=-\frac {e}{2 \left (c d^2+a e^2\right ) (d+e x)^2}-\frac {2 c d e}{\left (c d^2+a e^2\right )^2 (d+e x)}+\frac {c^{3/2} d \left (c d^2-3 a e^2\right ) \tan ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {a}}\right )}{\sqrt {a} \left (c d^2+a e^2\right )^3}+\frac {c e \left (3 c d^2-a e^2\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^3}-\frac {c e \left (3 c d^2-a e^2\right ) \log \left (a+c x^2\right )}{2 \left (c d^2+a e^2\right )^3}\\ \end {align*}

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Mathematica [A]
time = 0.20, size = 140, normalized size = 0.80 \begin {gather*} \frac {\frac {2 c^{3/2} d \left (c d^2-3 a e^2\right ) \tan ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {a}}\right )}{\sqrt {a}}+e \left (-\frac {\left (c d^2+a e^2\right ) \left (a e^2+c d (5 d+4 e x)\right )}{(d+e x)^2}+2 c \left (3 c d^2-a e^2\right ) \log (d+e x)+c \left (-3 c d^2+a e^2\right ) \log \left (a+c x^2\right )\right )}{2 \left (c d^2+a e^2\right )^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/((d + e*x)^3*(a + c*x^2)),x]

[Out]

((2*c^(3/2)*d*(c*d^2 - 3*a*e^2)*ArcTan[(Sqrt[c]*x)/Sqrt[a]])/Sqrt[a] + e*(-(((c*d^2 + a*e^2)*(a*e^2 + c*d*(5*d
+ 4*e*x)))/(d + e*x)^2) + 2*c*(3*c*d^2 - a*e^2)*Log[d + e*x] + c*(-3*c*d^2 + a*e^2)*Log[a + c*x^2]))/(2*(c*d^
2 + a*e^2)^3)

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Maple [A]
time = 0.53, size = 160, normalized size = 0.91

method	result	size
default	\(-\frac {e}{2 \left (e^{2} a +c \,d^{2}\right ) \left (e x +d \right )^{2}}-\frac {2 c d e}{\left (e^{2} a +c \,d^{2}\right )^{2} \left (e x +d \right )}-\frac {e c \left (e^{2} a -3 c \,d^{2}\right ) \ln \left (e x +d \right )}{\left (e^{2} a +c \,d^{2}\right )^{3}}-\frac {c^{2} \left (\frac {\left (-a \,e^{3}+3 c \,d^{2} e \right ) \ln \left (c \,x^{2}+a \right )}{2 c}+\frac {\left (3 a d \,e^{2}-c \,d^{3}\right ) \arctan \left (\frac {c x}{\sqrt {a c}}\right )}{\sqrt {a c}}\right )}{\left (e^{2} a +c \,d^{2}\right )^{3}}\)	\(160\)
risch	\(\frac {-\frac {2 d \,e^{2} c x}{a^{2} e^{4}+2 a c \,d^{2} e^{2}+c^{2} d^{4}}-\frac {\left (e^{2} a +5 c \,d^{2}\right ) e}{2 \left (a^{2} e^{4}+2 a c \,d^{2} e^{2}+c^{2} d^{4}\right )}}{\left (e x +d \right )^{2}}-\frac {c \,e^{3} \ln \left (e x +d \right ) a}{e^{6} a^{3}+3 e^{4} d^{2} a^{2} c +3 d^{4} e^{2} c^{2} a +d^{6} c^{3}}+\frac {3 c^{2} e \ln \left (e x +d \right ) d^{2}}{e^{6} a^{3}+3 e^{4} d^{2} a^{2} c +3 d^{4} e^{2} c^{2} a +d^{6} c^{3}}+\frac {\left (\munderset {\textit {\_R} =\RootOf \left (\left (e^{6} a^{4}+3 d^{2} e^{4} c \,a^{3}+3 d^{4} e^{2} a^{2} c^{2}+d^{6} c^{3} a \right ) \textit {\_Z}^{2}+\left (-2 a^{2} c \,e^{3}+6 c^{2} d^{2} a e \right ) \textit {\_Z} +c^{2}\right )}{\sum }\textit {\_R} \ln \left (\left (\left (3 a^{5} e^{10}+11 a^{4} c \,d^{2} e^{8}+14 a^{3} c^{2} d^{4} e^{6}+6 a^{2} c^{3} d^{6} e^{4}-a \,c^{4} d^{8} e^{2}-c^{5} d^{10}\right ) \textit {\_R}^{2}+\left (-3 e^{7} c \,a^{3}-d^{2} e^{5} a^{2} c^{2}+7 d^{4} e^{3} c^{3} a +5 d^{6} e \,c^{4}\right ) \textit {\_R} +8 d^{2} e^{2} c^{3}\right ) x +\left (4 a^{5} d \,e^{9}+16 a^{4} c \,d^{3} e^{7}+24 a^{3} c^{2} d^{5} e^{5}+16 a^{2} c^{3} d^{7} e^{3}+4 a \,c^{4} d^{9} e \right ) \textit {\_R}^{2}+\left (d \,e^{6} c \,a^{3}+3 d^{3} e^{4} a^{2} c^{2}+3 d^{5} e^{2} c^{3} a +d^{7} c^{4}\right ) \textit {\_R} +4 d \,e^{3} c^{2} a -4 d^{3} e \,c^{3}\right )\right )}{2}\)	\(542\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(e*x+d)^3/(c*x^2+a),x,method=_RETURNVERBOSE)

[Out]

-1/2*e/(a*e^2+c*d^2)/(e*x+d)^2-2*c*d*e/(a*e^2+c*d^2)^2/(e*x+d)-e*c*(a*e^2-3*c*d^2)/(a*e^2+c*d^2)^3*ln(e*x+d)-c
^2/(a*e^2+c*d^2)^3*(1/2*(-a*e^3+3*c*d^2*e)/c*ln(c*x^2+a)+(3*a*d*e^2-c*d^3)/(a*c)^(1/2)*arctan(c*x/(a*c)^(1/2))
)

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Maxima [A]
time = 0.55, size = 307, normalized size = 1.74 \begin {gather*} -\frac {{\left (3 \, c^{2} d^{2} e - a c e^{3}\right )} \log \left (c x^{2} + a\right )}{2 \, {\left (c^{3} d^{6} + 3 \, a c^{2} d^{4} e^{2} + 3 \, a^{2} c d^{2} e^{4} + a^{3} e^{6}\right )}} + \frac {{\left (3 \, c^{2} d^{2} e - a c e^{3}\right )} \log \left (x e + d\right )}{c^{3} d^{6} + 3 \, a c^{2} d^{4} e^{2} + 3 \, a^{2} c d^{2} e^{4} + a^{3} e^{6}} + \frac {{\left (c^{3} d^{3} - 3 \, a c^{2} d e^{2}\right )} \arctan \left (\frac {c x}{\sqrt {a c}}\right )}{{\left (c^{3} d^{6} + 3 \, a c^{2} d^{4} e^{2} + 3 \, a^{2} c d^{2} e^{4} + a^{3} e^{6}\right )} \sqrt {a c}} - \frac {4 \, c d x e^{2} + 5 \, c d^{2} e + a e^{3}}{2 \, {\left (c^{2} d^{6} + 2 \, a c d^{4} e^{2} + a^{2} d^{2} e^{4} + {\left (c^{2} d^{4} e^{2} + 2 \, a c d^{2} e^{4} + a^{2} e^{6}\right )} x^{2} + 2 \, {\left (c^{2} d^{5} e + 2 \, a c d^{3} e^{3} + a^{2} d e^{5}\right )} x\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^3/(c*x^2+a),x, algorithm="maxima")

[Out]

-1/2*(3*c^2*d^2*e - a*c*e^3)*log(c*x^2 + a)/(c^3*d^6 + 3*a*c^2*d^4*e^2 + 3*a^2*c*d^2*e^4 + a^3*e^6) + (3*c^2*d
^2*e - a*c*e^3)*log(x*e + d)/(c^3*d^6 + 3*a*c^2*d^4*e^2 + 3*a^2*c*d^2*e^4 + a^3*e^6) + (c^3*d^3 - 3*a*c^2*d*e^
2)*arctan(c*x/sqrt(a*c))/((c^3*d^6 + 3*a*c^2*d^4*e^2 + 3*a^2*c*d^2*e^4 + a^3*e^6)*sqrt(a*c)) - 1/2*(4*c*d*x*e^
2 + 5*c*d^2*e + a*e^3)/(c^2*d^6 + 2*a*c*d^4*e^2 + a^2*d^2*e^4 + (c^2*d^4*e^2 + 2*a*c*d^2*e^4 + a^2*e^6)*x^2 +
2*(c^2*d^5*e + 2*a*c*d^3*e^3 + a^2*d*e^5)*x)

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 399 vs. \(2 (163) = 326\).
time = 3.72, size = 821, normalized size = 4.66 \begin {gather*} \left [-\frac {4 \, c^{2} d^{3} x e^{2} + 5 \, c^{2} d^{4} e + 4 \, a c d x e^{4} + 6 \, a c d^{2} e^{3} + a^{2} e^{5} + {\left (2 \, c^{2} d^{4} x e + c^{2} d^{5} - 3 \, a c d x^{2} e^{4} - 6 \, a c d^{2} x e^{3} + {\left (c^{2} d^{3} x^{2} - 3 \, a c d^{3}\right )} e^{2}\right )} \sqrt {-\frac {c}{a}} \log \left (\frac {c x^{2} - 2 \, a x \sqrt {-\frac {c}{a}} - a}{c x^{2} + a}\right ) + {\left (6 \, c^{2} d^{3} x e^{2} + 3 \, c^{2} d^{4} e - a c x^{2} e^{5} - 2 \, a c d x e^{4} + {\left (3 \, c^{2} d^{2} x^{2} - a c d^{2}\right )} e^{3}\right )} \log \left (c x^{2} + a\right ) - 2 \, {\left (6 \, c^{2} d^{3} x e^{2} + 3 \, c^{2} d^{4} e - a c x^{2} e^{5} - 2 \, a c d x e^{4} + {\left (3 \, c^{2} d^{2} x^{2} - a c d^{2}\right )} e^{3}\right )} \log \left (x e + d\right )}{2 \, {\left (2 \, c^{3} d^{7} x e + c^{3} d^{8} + 6 \, a c^{2} d^{5} x e^{3} + 6 \, a^{2} c d^{3} x e^{5} + a^{3} x^{2} e^{8} + 2 \, a^{3} d x e^{7} + {\left (3 \, a^{2} c d^{2} x^{2} + a^{3} d^{2}\right )} e^{6} + 3 \, {\left (a c^{2} d^{4} x^{2} + a^{2} c d^{4}\right )} e^{4} + {\left (c^{3} d^{6} x^{2} + 3 \, a c^{2} d^{6}\right )} e^{2}\right )}}, -\frac {4 \, c^{2} d^{3} x e^{2} + 5 \, c^{2} d^{4} e + 4 \, a c d x e^{4} + 6 \, a c d^{2} e^{3} + a^{2} e^{5} - 2 \, {\left (2 \, c^{2} d^{4} x e + c^{2} d^{5} - 3 \, a c d x^{2} e^{4} - 6 \, a c d^{2} x e^{3} + {\left (c^{2} d^{3} x^{2} - 3 \, a c d^{3}\right )} e^{2}\right )} \sqrt {\frac {c}{a}} \arctan \left (x \sqrt {\frac {c}{a}}\right ) + {\left (6 \, c^{2} d^{3} x e^{2} + 3 \, c^{2} d^{4} e - a c x^{2} e^{5} - 2 \, a c d x e^{4} + {\left (3 \, c^{2} d^{2} x^{2} - a c d^{2}\right )} e^{3}\right )} \log \left (c x^{2} + a\right ) - 2 \, {\left (6 \, c^{2} d^{3} x e^{2} + 3 \, c^{2} d^{4} e - a c x^{2} e^{5} - 2 \, a c d x e^{4} + {\left (3 \, c^{2} d^{2} x^{2} - a c d^{2}\right )} e^{3}\right )} \log \left (x e + d\right )}{2 \, {\left (2 \, c^{3} d^{7} x e + c^{3} d^{8} + 6 \, a c^{2} d^{5} x e^{3} + 6 \, a^{2} c d^{3} x e^{5} + a^{3} x^{2} e^{8} + 2 \, a^{3} d x e^{7} + {\left (3 \, a^{2} c d^{2} x^{2} + a^{3} d^{2}\right )} e^{6} + 3 \, {\left (a c^{2} d^{4} x^{2} + a^{2} c d^{4}\right )} e^{4} + {\left (c^{3} d^{6} x^{2} + 3 \, a c^{2} d^{6}\right )} e^{2}\right )}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^3/(c*x^2+a),x, algorithm="fricas")

[Out]

[-1/2*(4*c^2*d^3*x*e^2 + 5*c^2*d^4*e + 4*a*c*d*x*e^4 + 6*a*c*d^2*e^3 + a^2*e^5 + (2*c^2*d^4*x*e + c^2*d^5 - 3*
a*c*d*x^2*e^4 - 6*a*c*d^2*x*e^3 + (c^2*d^3*x^2 - 3*a*c*d^3)*e^2)*sqrt(-c/a)*log((c*x^2 - 2*a*x*sqrt(-c/a) - a)
/(c*x^2 + a)) + (6*c^2*d^3*x*e^2 + 3*c^2*d^4*e - a*c*x^2*e^5 - 2*a*c*d*x*e^4 + (3*c^2*d^2*x^2 - a*c*d^2)*e^3)*
log(c*x^2 + a) - 2*(6*c^2*d^3*x*e^2 + 3*c^2*d^4*e - a*c*x^2*e^5 - 2*a*c*d*x*e^4 + (3*c^2*d^2*x^2 - a*c*d^2)*e^
3)*log(x*e + d))/(2*c^3*d^7*x*e + c^3*d^8 + 6*a*c^2*d^5*x*e^3 + 6*a^2*c*d^3*x*e^5 + a^3*x^2*e^8 + 2*a^3*d*x*e^
7 + (3*a^2*c*d^2*x^2 + a^3*d^2)*e^6 + 3*(a*c^2*d^4*x^2 + a^2*c*d^4)*e^4 + (c^3*d^6*x^2 + 3*a*c^2*d^6)*e^2), -1
/2*(4*c^2*d^3*x*e^2 + 5*c^2*d^4*e + 4*a*c*d*x*e^4 + 6*a*c*d^2*e^3 + a^2*e^5 - 2*(2*c^2*d^4*x*e + c^2*d^5 - 3*a
*c*d*x^2*e^4 - 6*a*c*d^2*x*e^3 + (c^2*d^3*x^2 - 3*a*c*d^3)*e^2)*sqrt(c/a)*arctan(x*sqrt(c/a)) + (6*c^2*d^3*x*e
^2 + 3*c^2*d^4*e - a*c*x^2*e^5 - 2*a*c*d*x*e^4 + (3*c^2*d^2*x^2 - a*c*d^2)*e^3)*log(c*x^2 + a) - 2*(6*c^2*d^3*
x*e^2 + 3*c^2*d^4*e - a*c*x^2*e^5 - 2*a*c*d*x*e^4 + (3*c^2*d^2*x^2 - a*c*d^2)*e^3)*log(x*e + d))/(2*c^3*d^7*x*
e + c^3*d^8 + 6*a*c^2*d^5*x*e^3 + 6*a^2*c*d^3*x*e^5 + a^3*x^2*e^8 + 2*a^3*d*x*e^7 + (3*a^2*c*d^2*x^2 + a^3*d^2
)*e^6 + 3*(a*c^2*d^4*x^2 + a^2*c*d^4)*e^4 + (c^3*d^6*x^2 + 3*a*c^2*d^6)*e^2)]

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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)**3/(c*x**2+a),x)

[Out]

Timed out

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Giac [A]
time = 1.27, size = 269, normalized size = 1.53 \begin {gather*} -\frac {{\left (3 \, c^{2} d^{2} e - a c e^{3}\right )} \log \left (c x^{2} + a\right )}{2 \, {\left (c^{3} d^{6} + 3 \, a c^{2} d^{4} e^{2} + 3 \, a^{2} c d^{2} e^{4} + a^{3} e^{6}\right )}} + \frac {{\left (3 \, c^{2} d^{2} e^{2} - a c e^{4}\right )} \log \left ({\left | x e + d \right |}\right )}{c^{3} d^{6} e + 3 \, a c^{2} d^{4} e^{3} + 3 \, a^{2} c d^{2} e^{5} + a^{3} e^{7}} + \frac {{\left (c^{3} d^{3} - 3 \, a c^{2} d e^{2}\right )} \arctan \left (\frac {c x}{\sqrt {a c}}\right )}{{\left (c^{3} d^{6} + 3 \, a c^{2} d^{4} e^{2} + 3 \, a^{2} c d^{2} e^{4} + a^{3} e^{6}\right )} \sqrt {a c}} - \frac {5 \, c^{2} d^{4} e + 6 \, a c d^{2} e^{3} + a^{2} e^{5} + 4 \, {\left (c^{2} d^{3} e^{2} + a c d e^{4}\right )} x}{2 \, {\left (c d^{2} + a e^{2}\right )}^{3} {\left (x e + d\right )}^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^3/(c*x^2+a),x, algorithm="giac")

[Out]

-1/2*(3*c^2*d^2*e - a*c*e^3)*log(c*x^2 + a)/(c^3*d^6 + 3*a*c^2*d^4*e^2 + 3*a^2*c*d^2*e^4 + a^3*e^6) + (3*c^2*d
^2*e^2 - a*c*e^4)*log(abs(x*e + d))/(c^3*d^6*e + 3*a*c^2*d^4*e^3 + 3*a^2*c*d^2*e^5 + a^3*e^7) + (c^3*d^3 - 3*a
*c^2*d*e^2)*arctan(c*x/sqrt(a*c))/((c^3*d^6 + 3*a*c^2*d^4*e^2 + 3*a^2*c*d^2*e^4 + a^3*e^6)*sqrt(a*c)) - 1/2*(5
*c^2*d^4*e + 6*a*c*d^2*e^3 + a^2*e^5 + 4*(c^2*d^3*e^2 + a*c*d*e^4)*x)/((c*d^2 + a*e^2)^3*(x*e + d)^2)

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Mupad [B]
time = 1.14, size = 745, normalized size = 4.23 \begin {gather*} \frac {\ln \left (d+e\,x\right )\,\left (3\,c^2\,d^2\,e-a\,c\,e^3\right )}{a^3\,e^6+3\,a^2\,c\,d^2\,e^4+3\,a\,c^2\,d^4\,e^2+c^3\,d^6}-\frac {\ln \left (c^2\,d^{10}\,{\left (-a\,c^3\right )}^{3/2}-9\,a^6\,e^{10}\,\sqrt {-a\,c^3}+9\,a^6\,c^2\,e^{10}\,x+106\,a^2\,d^6\,e^4\,{\left (-a\,c^3\right )}^{3/2}+a\,c^7\,d^{10}\,x+6\,a^4\,c^2\,d^4\,e^6\,\sqrt {-a\,c^3}+77\,a\,c\,d^8\,e^2\,{\left (-a\,c^3\right )}^{3/2}+77\,a^2\,c^6\,d^8\,e^2\,x+106\,a^3\,c^5\,d^6\,e^4\,x-6\,a^4\,c^4\,d^4\,e^6\,x-27\,a^5\,c^3\,d^2\,e^8\,x+27\,a^5\,c\,d^2\,e^8\,\sqrt {-a\,c^3}\right )\,\left (c\,\left (\frac {d^3\,\sqrt {-a\,c^3}}{2}-\frac {a^2\,e^3}{2}\right )+\frac {3\,a\,c^2\,d^2\,e}{2}-\frac {3\,a\,d\,e^2\,\sqrt {-a\,c^3}}{2}\right )}{a^4\,e^6+3\,a^3\,c\,d^2\,e^4+3\,a^2\,c^2\,d^4\,e^2+a\,c^3\,d^6}-\frac {\ln \left (c^2\,d^{10}\,{\left (-a\,c^3\right )}^{3/2}-9\,a^6\,e^{10}\,\sqrt {-a\,c^3}-9\,a^6\,c^2\,e^{10}\,x+106\,a^2\,d^6\,e^4\,{\left (-a\,c^3\right )}^{3/2}-a\,c^7\,d^{10}\,x+6\,a^4\,c^2\,d^4\,e^6\,\sqrt {-a\,c^3}+77\,a\,c\,d^8\,e^2\,{\left (-a\,c^3\right )}^{3/2}-77\,a^2\,c^6\,d^8\,e^2\,x-106\,a^3\,c^5\,d^6\,e^4\,x+6\,a^4\,c^4\,d^4\,e^6\,x+27\,a^5\,c^3\,d^2\,e^8\,x+27\,a^5\,c\,d^2\,e^8\,\sqrt {-a\,c^3}\right )\,\left (\frac {3\,a\,c^2\,d^2\,e}{2}-c\,\left (\frac {d^3\,\sqrt {-a\,c^3}}{2}+\frac {a^2\,e^3}{2}\right )+\frac {3\,a\,d\,e^2\,\sqrt {-a\,c^3}}{2}\right )}{a^4\,e^6+3\,a^3\,c\,d^2\,e^4+3\,a^2\,c^2\,d^4\,e^2+a\,c^3\,d^6}-\frac {\frac {5\,c\,d^2\,e+a\,e^3}{2\,\left (a^2\,e^4+2\,a\,c\,d^2\,e^2+c^2\,d^4\right )}+\frac {2\,c\,d\,e^2\,x}{a^2\,e^4+2\,a\,c\,d^2\,e^2+c^2\,d^4}}{d^2+2\,d\,e\,x+e^2\,x^2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((a + c*x^2)*(d + e*x)^3),x)

[Out]

(log(d + e*x)*(3*c^2*d^2*e - a*c*e^3))/(a^3*e^6 + c^3*d^6 + 3*a*c^2*d^4*e^2 + 3*a^2*c*d^2*e^4) - (log(c^2*d^10
*(-a*c^3)^(3/2) - 9*a^6*e^10*(-a*c^3)^(1/2) + 9*a^6*c^2*e^10*x + 106*a^2*d^6*e^4*(-a*c^3)^(3/2) + a*c^7*d^10*x
+ 6*a^4*c^2*d^4*e^6*(-a*c^3)^(1/2) + 77*a*c*d^8*e^2*(-a*c^3)^(3/2) + 77*a^2*c^6*d^8*e^2*x + 106*a^3*c^5*d^6*e
^4*x - 6*a^4*c^4*d^4*e^6*x - 27*a^5*c^3*d^2*e^8*x + 27*a^5*c*d^2*e^8*(-a*c^3)^(1/2))*(c*((d^3*(-a*c^3)^(1/2))/
2 - (a^2*e^3)/2) + (3*a*c^2*d^2*e)/2 - (3*a*d*e^2*(-a*c^3)^(1/2))/2))/(a^4*e^6 + a*c^3*d^6 + 3*a^3*c*d^2*e^4 +
3*a^2*c^2*d^4*e^2) - (log(c^2*d^10*(-a*c^3)^(3/2) - 9*a^6*e^10*(-a*c^3)^(1/2) - 9*a^6*c^2*e^10*x + 106*a^2*d^
6*e^4*(-a*c^3)^(3/2) - a*c^7*d^10*x + 6*a^4*c^2*d^4*e^6*(-a*c^3)^(1/2) + 77*a*c*d^8*e^2*(-a*c^3)^(3/2) - 77*a^
2*c^6*d^8*e^2*x - 106*a^3*c^5*d^6*e^4*x + 6*a^4*c^4*d^4*e^6*x + 27*a^5*c^3*d^2*e^8*x + 27*a^5*c*d^2*e^8*(-a*c^
3)^(1/2))*((3*a*c^2*d^2*e)/2 - c*((d^3*(-a*c^3)^(1/2))/2 + (a^2*e^3)/2) + (3*a*d*e^2*(-a*c^3)^(1/2))/2))/(a^4*
e^6 + a*c^3*d^6 + 3*a^3*c*d^2*e^4 + 3*a^2*c^2*d^4*e^2) - ((a*e^3 + 5*c*d^2*e)/(2*(a^2*e^4 + c^2*d^4 + 2*a*c*d^
2*e^2)) + (2*c*d*e^2*x)/(a^2*e^4 + c^2*d^4 + 2*a*c*d^2*e^2))/(d^2 + e^2*x^2 + 2*d*e*x)

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